Question

Line L passes through points (-2,1), (-4,-5). Find the equations of line L in the form y=mx + c.

Answer 1

y-y1=(y2-y1)/(x2-x1)(x-x1)
put x1=-2 y1=1 x2=-4 and y2=-5 then you have y-1=2(x+2)
this imply y=2x+5

Answer 2

@kunal28k

Answer 3

When I minused y2 and y1 I got -6 and therefore my equation read y=3x-2 ?

Answer 4

@ybarrap help

Answer 5

You are looking for m and c in this equation:

$$
y=mx+c
$$

To get it, use two points.

Using point (-2,1) we have that x=-2 and y=1:
$$
1=-2m+c
$$
Using point (-4,-5) we have that x=-4 and y=5:
$$
5=-4m+c
$$
So now we have two equations and two unknowns, m and c:
$$
1=-2m+c\\
5=-4m+c
$$
Solve this for m and c and substitute into
$$
y=mx+c
$$
And you are done. You will have an equation y in terms of x.

Make sense?

Answer 6

Great thank you very much for your help. This just made my life so much easier.