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Find dy/dx y=(116-21x^2)/120 Hi! I dont understand what to do here, please help!
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\[y=\frac{ 116-21x^2 }{ 120 }\] here is the equation again
\[y=\frac{116}{120}-\frac{21}{120}x^2\] therefore: \[y'=-\frac{21*2}{120}x^{2-1}\]\[=-\frac{21}{60}x\]
\[y= \frac{ 116 }{ 120 }-\frac{ 21x^{2} }{ 120 }\]
now find dy/dx
the \[\frac{ 116 }{ 120 } \] goes to zero when applying the power rule (I think thats what its called) right? and then the next part goes to \[\frac{ -21 }{ 60 }x\] but the answer in my text book says its -7x/20, so you divide both sides by three to get that
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-21x/60 (cancellation with 3 ) =-7x/20
u r right
Ok great! Thanks! :D
u r welcome:)
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