I think I can solve this problem, but not entirely sure. Help? It's absolute value.
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OpenStudy (anonymous):
Solve for x: −3|2x + 6| = −12
x = 1 and x = 5
x = −1 and x = −5
x = −9 and x = 3
No solution
OpenStudy (anonymous):
@amistre64 Could you show me?
OpenStudy (anonymous):
@Nnesha ?
Nnesha (nnesha):
yes first we need to get rid of everything at left side except the absolute bar
so move -3 to the right side
OpenStudy (anonymous):
Divide?
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Nnesha (nnesha):
right divide both sides by -3
Nnesha (nnesha):
let me know what you get after that so we can continue :=))
OpenStudy (anonymous):
um. -4
Nnesha (nnesha):
no negative divide by negative = positive
Nnesha (nnesha):
-12/-3= ?
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OpenStudy (anonymous):
Oh, okay. So +4
OpenStudy (anonymous):
Positive 4.
Nnesha (nnesha):
right \[\left| 2x+ 6\right|=4\]
absolute contains two solution
\[\left| 2x+6 \right| \rightarrow (2x+6)^2\]
absolute bar of 2x+6 is same as square of (2x+6)
and when take square root we should get plus/minus answer \[\sqrt{x^2}= \pm x\]
OpenStudy (anonymous):
What?
Nnesha (nnesha):
\[\left| 2x+6 \right|=4 \rightarrow 2x+6=4 ~\rm and~ 2x+6= -4\]
now solve both equation for x
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OpenStudy (anonymous):
Subtract 6 from both sides?
Nnesha (nnesha):
if the absolute bar equal to positive number
then you will get 2 solution here is an example \[\left| a+b \right|=c\]\[a+b = c ~~\rm and ~~ a+b=-c\]
Nnesha (nnesha):
yes right
OpenStudy (anonymous):
Okay so 2x=-2?
Nnesha (nnesha):
for first equation yes 2x = -2
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Nnesha (nnesha):
solve for x
OpenStudy (anonymous):
Divide. x= -1?
Nnesha (nnesha):
right
Nnesha (nnesha):
2nd equation
OpenStudy (anonymous):
-6 both sides?
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Nnesha (nnesha):
right
OpenStudy (anonymous):
So, -10.
OpenStudy (anonymous):
2x=-10
OpenStudy (anonymous):
-5?
Nnesha (nnesha):
looks good
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