what is the first step in writing f(x)=3x^2+6x-8 in vertex form?
A.factor out 3 from each term.
B. form a perfect square trinomial by keeping the value of the fuction equivalent.
C. write the trinomial as a binomial squared
D. factor out 3 from the first two terms
@Mchilds15

Question

what is the first step in writing f(x)=3x^2+6x-8 in vertex form?
A.factor out 3 from each term.
B. form a perfect square trinomial by keeping the value of the fuction equivalent. 
C. write the trinomial as a binomial squared 
D. factor out 3 from the first two terms
@Mchilds15

mchilds15 · Answer

Do you know what vertex form is?

anonymous · Answer

would this be it f (x) = a(x - h)2 + k, where (h, k) is the vertex

mchilds15 · Answer

And do you know what the a is for?

mchilds15 · Answer

And the k?

anonymous · Answer

no

anonymous · Answer

?

mchilds15 · Answer

All this problem is asking is for you to change the problem from standard form to vertex form. And really, it just wants you to know the first step. 

The a is basically the giveaway to if the function opens up or down.
And k is the y intercept.

mchilds15 · Answer

So what do you think is the first step ?

anonymous · Answer

D.factor out 3 from the first two terms

anonymous · Answer

Mchilds15

mchilds15 · Answer

I don't think D would work. 

When solving an equation, you can't necessarily single out the two variables. If you're factoring, you have to factor all the numbers, not just the first two.

Personally I would go with A.

anonymous · Answer

thank you it was right

mchilds15 · Answer

Of course it was ;)
Medal? lol

anonymous · Answer

the answer was D

mchilds15 · Answer

Oh sht, i see now. Because it's 3x, it would be the first -two- factors. 
My bad, honest mistake.