PLEASE HELP!!!! I WILL FAN AND MEDAL!!!!!
Solve x^2 + 12x + 6 = 0 using the completing-the-square method. A.) x = -6 + or - the square root of 30 B.) x = 6 + or - the square root of 30 C.) x = -6 + or - the square root of 6 D.) x = 6 + or - the square root of 6
I don't even remember the completing-the-square method! Let me refresh my memory then I'll get back to you.
Ok thanks :) @Hulk_Smash
Maybe this sites might help: http://www.purplemath.com/modules/solvquad3.htm https://www.khanacademy.org/math/algebra2/polynomial-and-rational/quad_formula_tutorial/v/solving-quadratic-equations-by-completing-the-square
I already looked at both sites earlier and i still dont understand how to solve the problem @Hulk_Smash
(x^2 +2* x* 6+6^2) -6^2+6=0 (we are add and subtract 6^2 )
(x+6)^2 -36+6=0
do u following
yes
r u there
so x^2 + 6 = 0? @dayakar
no
(x+6)^2-30 =0
(x+6)^2 =30
\[x+6 = + or -\sqrt{30}\]
so x = -6 + or - square root of 30? @dayakar
no
x+6= sqrt30 or x+6 =-sqrt30
but you subtract 6 from both sides
your options are wrong
\[x=-6+\sqrt{30}\] or
\[x= -6-\sqrt{30}\]
is it clear
that's what I said but ok XD thanks @dayakar
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