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Mathematics 6 Online
OpenStudy (yaya090600):

PLEASE HELP!!!! I WILL FAN AND MEDAL!!!!!

OpenStudy (yaya090600):

Solve x^2 + 12x + 6 = 0 using the completing-the-square method. A.) x = -6 + or - the square root of 30 B.) x = 6 + or - the square root of 30 C.) x = -6 + or - the square root of 6 D.) x = 6 + or - the square root of 6

OpenStudy (anonymous):

I don't even remember the completing-the-square method! Let me refresh my memory then I'll get back to you.

OpenStudy (yaya090600):

Ok thanks :) @Hulk_Smash

OpenStudy (yaya090600):

I already looked at both sites earlier and i still dont understand how to solve the problem @Hulk_Smash

OpenStudy (dayakar):

(x^2 +2* x* 6+6^2) -6^2+6=0 (we are add and subtract 6^2 )

OpenStudy (dayakar):

(x+6)^2 -36+6=0

OpenStudy (dayakar):

do u following

OpenStudy (yaya090600):

yes

OpenStudy (dayakar):

r u there

OpenStudy (yaya090600):

so x^2 + 6 = 0? @dayakar

OpenStudy (dayakar):

no

OpenStudy (dayakar):

(x+6)^2-30 =0

OpenStudy (dayakar):

(x+6)^2 =30

OpenStudy (dayakar):

\[x+6 = + or -\sqrt{30}\]

OpenStudy (yaya090600):

so x = -6 + or - square root of 30? @dayakar

OpenStudy (dayakar):

no

OpenStudy (dayakar):

x+6= sqrt30 or x+6 =-sqrt30

OpenStudy (yaya090600):

but you subtract 6 from both sides

OpenStudy (dayakar):

your options are wrong

OpenStudy (dayakar):

\[x=-6+\sqrt{30}\] or

OpenStudy (dayakar):

\[x= -6-\sqrt{30}\]

OpenStudy (dayakar):

is it clear

OpenStudy (yaya090600):

that's what I said but ok XD thanks @dayakar

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