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OpenStudy (yaya090600):
PLEASE HELP!!!! I WILL FAN AND MEDAL!!!!!
10 years ago
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OpenStudy (yaya090600):
Solve x^2 + 12x + 6 = 0 using the completing-the-square method.
A.) x = -6 + or - the square root of 30
B.) x = 6 + or - the square root of 30
C.) x = -6 + or - the square root of 6
D.) x = 6 + or - the square root of 6
10 years ago
OpenStudy (anonymous):
I don't even remember the completing-the-square method! Let me refresh my memory then I'll get back to you.
10 years ago
OpenStudy (yaya090600):
Ok thanks :) @Hulk_Smash
10 years ago
OpenStudy (yaya090600):
I already looked at both sites earlier and i still dont understand how to solve the problem @Hulk_Smash
10 years ago
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OpenStudy (dayakar):
(x^2 +2* x* 6+6^2) -6^2+6=0 (we are add and subtract 6^2 )
10 years ago
OpenStudy (dayakar):
(x+6)^2 -36+6=0
10 years ago
OpenStudy (dayakar):
do u following
10 years ago
OpenStudy (yaya090600):
yes
10 years ago
OpenStudy (dayakar):
r u there
10 years ago
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OpenStudy (yaya090600):
so x^2 + 6 = 0? @dayakar
10 years ago
OpenStudy (dayakar):
no
10 years ago
OpenStudy (dayakar):
(x+6)^2-30 =0
10 years ago
OpenStudy (dayakar):
(x+6)^2 =30
10 years ago
OpenStudy (dayakar):
\[x+6 = + or -\sqrt{30}\]
10 years ago
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OpenStudy (yaya090600):
so x = -6 + or - square root of 30? @dayakar
10 years ago
OpenStudy (dayakar):
no
10 years ago
OpenStudy (dayakar):
x+6= sqrt30 or x+6 =-sqrt30
10 years ago
OpenStudy (yaya090600):
but you subtract 6 from both sides
10 years ago
OpenStudy (dayakar):
your options are wrong
10 years ago
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OpenStudy (dayakar):
\[x=-6+\sqrt{30}\]
or
10 years ago
OpenStudy (dayakar):
\[x= -6-\sqrt{30}\]
10 years ago
OpenStudy (dayakar):
is it clear
10 years ago
OpenStudy (yaya090600):
that's what I said but ok XD thanks @dayakar
10 years ago
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