WILL GIVE MEDAL!!! PLEASE HELP!!
M=y2-y1 (over) x2-x1
solve for y2

Question

WILL GIVE MEDAL!!! PLEASE HELP!!
M=y2-y1 (over) x2-x1
solve for y2

mathstudent55 · Answer

$\large m = \dfrac{y_2 - y_1}{x_2 - x_1} $

mathstudent55 · Answer

We are solving for $y_2$.
Since $y_2$ is on the right side, let's start by switching sides.

$\large \dfrac{y_2 - y_1}{x_2 - x_1} = m$

anonymous · Answer

okay

mathstudent55 · Answer

There is no $y_2$ in the denominator, so we can multiply both sides by the denominator of the left side.

mathstudent55 · Answer

$\large \dfrac{y_2 - y_1}{\cancel{x_2 - x_1}} \times (\cancel{x_2 - x_1}) = m\times (x_2 - x_1)$

$\large y_2 - y_1 = m(x_2 - x_1)$

Now you only need one more step to finish.

mathstudent55 · Answer

Since you want $y_2$ alone, you need to add $y_1$ to both sides.

mathstudent55 · Answer

$\large y_2 \cancel{- y_1} + \cancel{y_1}= m(x_2 - x_1) + y_1$

$\large y_2 = m(x_2 - x_1) + y_1$