Question

WILL GIVE MEDAL!!! PLEASE HELP!!
M=y2-y1 (over) x2-x1
solve for y2

Answer 1

\(\large m = \dfrac{y_2 - y_1}{x_2 - x_1} \)

Answer 2

We are solving for \(y_2\).
Since \(y_2\) is on the right side, let's start by switching sides.

\(\large \dfrac{y_2 - y_1}{x_2 - x_1} = m\)

Answer 3

okay

Answer 4

There is no \(y_2\) in the denominator, so we can multiply both sides by the denominator of the left side.

Answer 5

\(\large \dfrac{y_2 - y_1}{\cancel{x_2 - x_1}} \times (\cancel{x_2 - x_1}) = m\times (x_2 - x_1)\)

\(\large y_2 - y_1 = m(x_2 - x_1)\)

Now you only need one more step to finish.

Answer 6

Since you want \(y_2\) alone, you need to add \(y_1\) to both sides.

Answer 7

\(\large y_2 \cancel{- y_1} + \cancel{y_1}= m(x_2 - x_1) + y_1\)

\(\large y_2 = m(x_2 - x_1) + y_1\)