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Do the operation in the numerator first. In the numerator, you are multiplying powers with the same base. Add the exponents.
Remember, a^-x=1/a^x
\(\large \dfrac{5^{-6} \cdot 5^2}{5^{-8}} =\) \(= \large \dfrac{5^{-6+2}}{5^{-8}} \) What is \(-6 + 2\) ?
8
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sorry lol i hade to cahndge my pc a little bit
Notice the 6 is negative. It is not 6 + 2. That would be 8. It is -6 + 2. What is -6 + 2?
8
No. Let's say the temperature is -6 degrees. Then the temperature goes up 2 degrees. What temperature is it now?
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i thought i was adding lol
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