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Algebra
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Please help! Will give medal! 4. What is the vertex form of the equation below? y=x^2+4x-3
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first coordinate of the vertex is \(-\frac{b}{2a}\) which in your case is \[-\frac{4}{2\times 1}=-2\]
second coordinate of the vertex is is what you get when you replace \(x\) by \(-2\)
once you have your vertex \((h,k)\) vertex form is \[y=(x-h)^2+k\]
@satellite73 Oh, I get it. Soo... you replace x with -2, and you get y=-7, right?
So does it become y=(x-2)^2-7?
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I'm assuming that's the answer... thanks for the help @satellite73 ! Sorry for not being here when you replied! :(
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