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OpenStudy (amistre64):
when x=0, what is y?
OpenStudy (gokuporter):
2
OpenStudy (amistre64):
then our y intercept ... is at 2
OpenStudy (amistre64):
is our slope + or -?
OpenStudy (gokuporter):
Positive
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OpenStudy (amistre64):
then we want a line, with postivie slope, going thru y=2
OpenStudy (gokuporter):
Yes :)
OpenStudy (amistre64):
line C fails in that it is not going thru y=2
OpenStudy (gokuporter):
b?
OpenStudy (amistre64):
when y=0, what is x?
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OpenStudy (gokuporter):
5
OpenStudy (amistre64):
no
OpenStudy (amistre64):
-2x = 10
OpenStudy (amistre64):
we want a line going thru x=-5, and y=2
OpenStudy (gokuporter):
Which is a
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OpenStudy (amistre64):
then lets go with A :)
OpenStudy (gokuporter):
OK :)
OpenStudy (mathstudent55):
You can solve for y and read the slope and y-intercept directly.
\(-2x + 5y = 10\)
\(5y = 2x + 10\)
\(y = \color{red}{\dfrac{2}{5}}x + \color{green}{2}\)
Compare with
\(y = \color{red}{m}x + \color{green}{b}\)
where \(\color{red}{m} \) is the slope, and \(\color{green}{b}\) is the y-intercept.
That means we have a positive slope and a y-intercept of 2.
|dw:1445821083824:dw|
OpenStudy (gokuporter):
Thanks for the explanation :)
OpenStudy (gokuporter):
??
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