Please help, I will medal and fan 4. 3+d<3-d 5. The sum of two consecutive integers is at least 46. What is the least possible pair of integers? 21 and 23 23 and 24 22 and 23 24 and 25
3+d < 3-d Add d on both sides Tell me what you get :)
Basically think of the inequality as an equal sign :)
d>6?
Well let me see... mhmm... 3 + d < 3 - d 3 + 2d < 3 Subtract 3 on both sides 2d < 0 Divide by 2 on both sides d < 0
So that's wrong :P
oh, ok I see what you did.
can you help me with number 5?
sure :)
Consecutive integers means like back to back, so like x and (x + 1)
and the sum of the two consecutive integers is at least 46 so... x + x + 1 \(\ge\) 46 2x + 1 \(\ge\) 46 Solve for x :)
2x + 47 dividing 2x on both sides would give me 23.5
So that means that both numbers over 2 = 23.5
That would mean if one number is 23 and the other is 24, (23+24)/2 = 23.5
so b
yes
Thanks so much! here is you medal and fan
No problem (:
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