Please help, I will medal and fan
4. 3+d<3-d
5. The sum of two consecutive integers is at least 46. What is the least possible pair of integers?
21 and 23
23 and 24
22 and 23
24 and 25
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abdullahm):
3+d < 3-d
Add d on both sides
Tell me what you get :)
OpenStudy (abdullahm):
Basically think of the inequality as an equal sign :)
OpenStudy (anonymous):
d>6?
OpenStudy (abdullahm):
Well let me see... mhmm...
3 + d < 3 - d
3 + 2d < 3
Subtract 3 on both sides
2d < 0
Divide by 2 on both sides
d < 0
OpenStudy (abdullahm):
So that's wrong :P
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh, ok I see what you did.
OpenStudy (anonymous):
can you help me with number 5?
OpenStudy (abdullahm):
sure :)
OpenStudy (abdullahm):
Consecutive integers means like back to back, so like x and (x + 1)
OpenStudy (abdullahm):
and the sum of the two consecutive integers is at least 46
so...
x + x + 1 \(\ge\) 46
2x + 1 \(\ge\) 46
Solve for x :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
2x + 47
dividing 2x on both sides would give me 23.5
OpenStudy (abdullahm):
So that means that both numbers over 2 = 23.5
OpenStudy (abdullahm):
That would mean if one number is 23 and the other is 24, (23+24)/2 = 23.5
OpenStudy (anonymous):
so b
OpenStudy (abdullahm):
yes
Still Need Help?
Join the QuestionCove community and study together with friends!