Question

need help
A ball is thrown upward, and its height, h, in metres above the ground after t seconds is given by h(t)= -5t^2+25t, t>0.
a. Calculate the ball’s initial velocity.
b. Calculate its maximum height.
c. When does the ball strike the ground, and what is its velocity at this time?

Answer 1

\[s(t)=-g t^2+v_0t+h_0 \\ \text{ where } g \text{ is the force of gravity } \\ \text{ and } v_0 \text{ is initial velocity } \\ \text{ and } h_0 \text{ is initial height }\]
then answer is already given for a) no work needed

Answer 2

for b you will need to determine the vertex and the y-coordinate will be the max height since -5<0

Answer 3

for c you will find the ball will strike the ground when the height to ground is 0
in other words when h is 0
so you have h(t)=0 for t

Answer 4

you can find the velocity there by finding h'(t)
and then inserting the value for t you found for when h(t)=0
(use the second t because this when the ball strikes the ground)

Answer 5

@TorilovesVampires lol these are the steps i guess

Answer 6

Let me take a look

Answer 7

go ahead

Answer 8

Step 1) you have a science project due monday morning but the school dance is tomorrow (saturday) and you procrastinated.
Step 2) You can either start on it now since its friday and hopefully get most done then stay up super late sunday or you can just get up super early monday morning to get it done.
Step 3) Choose either decison.
Step 4) Get up at 5:45am (you dont wake up normally til 7:30am)
Step 5) it can either go really good or really bad (you decide take outcome)

Answer 9

@TorilovesVampires look at this one

Answer 10

That's really good

Answer 11

ok so

Answer 12

Yes

Answer 13

do you wanna change any thing there because i am not sure if is it right