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Mathematics 18 Online
OpenStudy (anonymous):

Refer to the triangle and compute the quantities indicated. (Enter your answers in exact form.) a) sin(s/2) b) cos(s/2)

OpenStudy (anonymous):

OpenStudy (anonymous):

I need heeeeeeeelp.

OpenStudy (anonymous):

Sine = Opp / Hypotenuse Cosine = Adj / Hypotenuse.....Need to determine your hypotenuse first

OpenStudy (anonymous):

Ok, so what is the hypotenuse?

OpenStudy (anonymous):

a^2 +b^2=c^2

OpenStudy (anonymous):

wouldn't it be 26?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Ok after that what do I do?

OpenStudy (anonymous):

SIne(s) = opposite side / hypotenuse

OpenStudy (anonymous):

Opposite side from the s angle

OpenStudy (anonymous):

ok, but when do I have to divide by 2?

OpenStudy (anonymous):

Since it's sin (s/2)

OpenStudy (anonymous):

I assume so ....

OpenStudy (anonymous):

Strange question...I would compute my value for s, then divide by 2....do they want you to convert to degrees?

OpenStudy (anonymous):

Nope, they want it in fraction form, like in exact form. It's webassign and they have a lot of requirements.

OpenStudy (tkhunny):

You should probably use the half-angle formulas. \(\sin(s/2) = \sqrt{\dfrac{1-\cos(s)}{2}}\) for triangles. \(\cos(s/2) = \sqrt{\dfrac{1+\cos(s)}{2}}\) for triangles.

OpenStudy (anonymous):

Yep..tkbunny is right

OpenStudy (anonymous):

determine cos(s) by adjacent / hypotenuse then plug into the formulas above....sorry I forgot about 1/2 angles

OpenStudy (anonymous):

I'm still slightly confused, like how exactly I'm I supposed to plug it in the calculator?

OpenStudy (anonymous):

cosine (10/26) what do you get?

OpenStudy (tkhunny):

You don't use a calculator. Just write down the exact expression. \(\cos(s) = 10/26 = 5/13\) \(\sin(s/2) = \sqrt{\dfrac{1-(5/13)}{2}} = \sqrt{\dfrac{4}{13}} = \dfrac{2}{\sqrt{13}}\) Do the same for the cosine.

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