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Verify the identity. cotx minus pi divided by two. = -tan x
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\[\cot (x-\Pi/2)=-tanx\]
familiar with Cofunctions Identities?
you also need to familiar with negative angle identities \[\rm \sin(-x) = -\sin(x) ~~~\color{red}{odd}\]\[\rm \cos(-x)= \cos(x)~~~~~\color{red}{even}\]\[\rm Tan(-x)=-\tan(x)~~\color{red}{odd}\]
\[\rm \cot (x-\frac{\pi}{2} )~ can ~be~written~as~\cot (-\frac{\pi}{2}+x)\] now first take out the negative sign and then use Cofunctions identity here is the link if you don't know about it http://www.analyzemath.com/trigonometry/trigonometric_formulas.html
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