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Find linearization L(x) of the function at a.
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\[f(x)=x ^{2/3} , a=64\]
\[f(64)=64^{2/3}=\sqrt[3]{64}^{2}=(4)^{2}=16\] f'(x)=\[\frac{ 2 }{ 3 }x ^{-1/3}\]
HI!!
hello
translate as "find the equation for the line given a point and a slope"
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\[f'(64)=\frac{ 2 }{ 3 }(64)x ^{-1/3}\]
=1/6
the point is \((64,8)\) and the slope is whatever the derivative is when you plug in \(64\) i.e. \[f'(64)\]
ok you are pretty much done
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