Question

what is e^j5t(1+j sqrt(3)) ?

Answer 1

when i turn (1+j sqrt(3)) into polar from is gives me 2(cos2pi3 +sin2pi/3)

Answer 2

@ganeshie8 could you please explain this?

Answer 3

\[ e^{j5t(1+j \sqrt(3)} \] confused

Answer 4

\[1+i\sqrt3=2(\cos(\frac{\pi}{3})+i\sin(\frac{\pi}{3}))\] is correct though

Answer 5

or if you prefer \[\huge 2e^{\frac{\pi}{3}i}\]

Answer 6

is the first part \[e^{5jt}\]? what is \(t\)?

Answer 7

that what i got, but apparently the answer is

Answer 8

they made a mistake. \( 1 + j \sqrt{3} = 2 e^{j \frac{\pi}{3}} \)
not \( 2 e^{j \frac{\pi}{6}} \)