Math help, will medal.
whats you math problem?
1. If g(x) = 2x- x +5 , then g (2) = __. (1 point) 2 6 7 9 19
Im thinking its 7.
Substitute 2 for all of the x's to get 2(2)-2+5=4-2+5=2+5=7. So yes you are correct.
Hey Thanks I have a few more can you help? Ill make a new post, so I can medal you again!
I can try :)
Heres 2-4 if you'll take a look at them.
Im thinking A, C, D
g(x) = 2(2) - 2 +5 g(x) = 4-2+5 g(x) = 2+5 g(x)= 7
g(2)= 2(2)-2+5 step1: 2*2=4 step2: 4-2=2 step3: 2+5=7. Just plug in a 2 where ever you see an x and follow the mathematical opertation through to completion. (g(2) for g(x) means exactly that, you are given a value for the variable x, so go to it and plug it in!)
Yeah
I posted another question guys! Thnak you!
ok
Lets see
For number 2 you need to substitute all the a's for 3 and all of the b's for 2. So now it's going to be 3^2 -2^2/3+2. So solving that is 9-4/5=5/5=1
Okay Ill send it through again. Im thinking A, C, D
Okay so @kimbllse777 Its 1, not -5?
Yes
Okay thank you!
For 3 substitute all of the c's for 2 and all of the d's for 1. So it will look like 2^2 + 1^2 -4= 4+1-4=5-4=1
Okay so for number three I plugged the numbers as well. 2 and 1=2^2+1^2-4 2 and 1= 4+1-4 2 and 1= 5-4=1 so 1 again?
LOL OK Cool one more then Ill make another post and tag you.
And the last one. a*b=a^2-2ab+b^2/a-b 3x4= 3^2-2(3*4)+4^2/3-4 3*4= 9-2(12)+16/1 3*4= 7(12)+16/1 3*4= 84+16/1 3*4=100/1 Im not sure if I did something wrong but that's not one of the answer choices...
For 5 you need to substitute all of the a's for 3 and all of the b's for 4. So now it will be 3^2-2(3)(4)+4^2/3-4 = 9-2(3)(4)+16/3-4 = 9-24+16/-1 = -15+16/-1 = 1/-1 = -1
Okay Yours make wayyy more sense! Thanks for explaining. Ill close this in tag you in another one!
Do you see where you went wrong?
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