Question

please help me...

Answer 1

find the nth derivative of \[\sin^3(3x)\]

Answer 2

@Empty @BAdhi @Callisto @tkhunny

Answer 3

Have you considered finding the first few derivatives and establishing a predictable pattern?

Answer 4

well i cant keep on finding the pattern during my exam time :(

Answer 5

successive is tough :(

Answer 6

Well, during your exam, we also don't respond to cheating. How can I help you with that? I can track down your IP and report cheating to your school. Is that where we are?

Answer 7

lol
i m not giving exam now @tkhunny im practising sums
but during the exam tym i cant keep on findng the ssuccessive differentiation one by one since i will have other questions too to solve with limited time


i dont cheat. im against cheating

Answer 8

Lol I don't think he's cheating

Answer 9

thank you @Empty

Answer 10

I'm only going on what was stated. I made no assumption.

It is likely that there are difficult questions on your exam. It is possible that such a problem will be on your exam, but anyone writing such a question should know that it might be time-consuming and put fewer other question on the exam. The purpose of this practice problem may be to increase your familiarity with the effort and such a thing will not be on the exam. Frankly, if it's on the practice exam, why are you hoping it's not on the real exam.

You have shown no work on this problem. Please respond appropriately to my first suggestion. Get faster at it and your complaint disappears.

Answer 11

It is often the case with trigonometric expressions that you can pull out your best trig identities and simplify the expression significantly. You may wish to explore this.

Answer 12

we have sin3x=3sinx-4sin^3x