Question

Solve this system of equation.
y = −x2 + 4
y = 2x + 1

Answer 1

\(\large\color{black}{ \displaystyle y=-x^2+4 }\)
\(\large\color{black}{ \displaystyle y=2x+1 }\)

We know that both \(\large\color{black}{ \displaystyle 2x+1 }\) and \(\large\color{black}{ \displaystyle -x^2+4 }\) are equivalent to \(\large\color{black}{ \displaystyle y }\),
therefore we can set up the following:

\(\large\color{black}{ \displaystyle 2x+1=-x^2+4 }\)

Answer 2

rearrange this,

\(\large\color{black}{ \displaystyle x^2+2x-3=0 }\)

Answer 3

Now, you just need to solve this quadratic for x, and then solve for y.