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a ≠b and 1/x+ 1/a = 1/b then x= A. 1/b= 1/a B. b-a C. 1/ab D. a-b/ab E. ab/a-b
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\[\frac{ 1 }{ x }=\frac{ 1 }{ b }-\frac{ 1 }{ a }=\frac{ a-b }{ ab },x=?\]
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\[\frac{1}{x}+\frac{1}{a}=\frac{1}{b}\]?
subtract \(\frac{1}{a}\) from both sides as @surjithaer wrote
you get \[\frac{1}{x}=\frac{1}{b}-\frac{1}{a}\] then do the subtraction do you know how to subtract \[\frac{1}{a}-\frac{1}{b}\]?
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is either E or D then?
E or D are letters you have to subtract
then is A
thanks <3
A doesn't even make sense you are solving for \(x\) and A says \[\frac{1}{b}=\frac{1}{a}\]
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it has to be c then
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