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Mathematics 16 Online
OpenStudy (youngnephew34):

The rectangles in figure below are similar. find the value x A) 2.4 B) 2.7 C) 6 D) 6.7 <------- can somebody double check this PLZZZZZZZZZ FAN AND MEDAL

OpenStudy (mrnood):

we need the diagram....

OpenStudy (youngnephew34):

oh ok

OpenStudy (youngnephew34):

OpenStudy (anonymous):

I'm working on it now. I think I know how to do it.

OpenStudy (youngnephew34):

ok I got a question

OpenStudy (anonymous):

What's your question?

OpenStudy (youngnephew34):

ok I did 4x5= 20 right and then I did 20/3=6.666666667 and then I rounded it up and it gave me 6.7

OpenStudy (youngnephew34):

don't you suppose to do it like that

OpenStudy (anonymous):

I'm guessing. I kept getting x = 10. I'll just go with our answer. Sorry.

OpenStudy (youngnephew34):

are you sure

OpenStudy (emmatassone):

Why you did that?

OpenStudy (youngnephew34):

did what?

OpenStudy (emmatassone):

did 4x5= 20 and then you did 20/3=6.666666667 and then you rounded it up

OpenStudy (youngnephew34):

because aren't you suppose to round it to the highest tens

OpenStudy (emmatassone):

i mean why you did 4x5 and then you divided by 3

OpenStudy (youngnephew34):

ok Look at the problem

OpenStudy (emmatassone):

i ve already looked at it

OpenStudy (emmatassone):

but i dont understand why you did tht

OpenStudy (youngnephew34):

that's how I figure it out I can't explain it

OpenStudy (emmatassone):

you should do procedures you cant explain because that means they are no reasonable and therefore they are wrong.

OpenStudy (emmatassone):

in your procedure you've never used the information about the similar rectangles

OpenStudy (youngnephew34):

ok Look how do you found x so the only choice is to do 4x5=20 right and then do 20/3=6.666666667 and the round that 6 up and it will give you 6.7

OpenStudy (emmatassone):

If they are similar, then the base and height are proportionally equal. \[\frac{ B1 }{ H1 }=\frac{ B2 }{ H2 }\]So, applying this to the actual problem:\[\frac{ x+4 }{ 5 }=\frac{ x }{ 3 }\] \[3x+12=5x\] Finally you have to resolve this equation to find x

OpenStudy (emmatassone):

and trust me, if you cant justify what you are doing, please dont do it. It just a helpful advice

OpenStudy (youngnephew34):

Don't you suppose to subtract the variables first

OpenStudy (emmatassone):

why?

OpenStudy (youngnephew34):

so you saying 3x+12=5x right

OpenStudy (emmatassone):

The Base of the bigger rectangle is x+4 and the base of the other is x, the height of the bigger is 5 and the height of the other is 3. I just plot this information in the first equation

OpenStudy (emmatassone):

yep

OpenStudy (youngnephew34):

So If you doing 3x+12=5x don't you subtract the variables

OpenStudy (emmatassone):

Oh yes , i left to you that work

OpenStudy (emmatassone):

when you substract the variables and resolve the equation you will find x

OpenStudy (youngnephew34):

ok I did 3 on both sides so I canceled out the 3-3 and did 15-3 and gave me 12

OpenStudy (emmatassone):

what?

OpenStudy (emmatassone):

do you know how to resolve and equation?

OpenStudy (mrnood):

@youngnephew34 @EmmaTassone is correct the ratio of the sides is x+4/5 and x/3 since the shapes are similar then thes two ratios are EQUAL the equation given by @EmmaTassone above will lead to the correct answer

OpenStudy (youngnephew34):

pk Look you are doing 3 on both sides so cancel out the 3-3 and do 15-3 and it gave me 12

OpenStudy (youngnephew34):

so if I jump the 12 in the middle of the equation how do 12=12

OpenStudy (mrnood):

3x+12=5x SUBTRACT 3x from each side of the equation... write the result here....

OpenStudy (youngnephew34):

that's what I am saying

OpenStudy (mrnood):

so - do it

OpenStudy (emmatassone):

you did it wrong, try doing it again

OpenStudy (youngnephew34):

so I did 5-3 and it gave me 2

OpenStudy (emmatassone):

yep

OpenStudy (mrnood):

it's 5x - 3x NOT 5-3

OpenStudy (youngnephew34):

you going to do 12=2x

OpenStudy (mrnood):

correct

OpenStudy (youngnephew34):

6=x

OpenStudy (emmatassone):

well, thats the final solution

OpenStudy (mrnood):

now check it by looking at the ratio of the rectangle sides...

OpenStudy (youngnephew34):

so plug in the 6 into the x

OpenStudy (mrnood):

yes then what is the ration of the sides of the BIG rectangle? what is the ration of the sides of the SALL rectangle?

OpenStudy (mrnood):

^^ ratio ... not ration!

OpenStudy (youngnephew34):

ummmmmmm so you would do 3(6)+12=5(6)

OpenStudy (mrnood):

NO If x = 6 then divide the long side of the small rectangle by the short side of the small rectangle then divide the long side of the large rectangle by the short side of the large rectangle If thase two values are the SAME - then your answer (x=6) is correct

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