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find the solution set for this equation -b^2-5b=0
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I would first multiply both sides (and all terms) by -1 that way you get b^2 +5b=0 now factor "b" out of each term. can you do that ?
yes
you should get b(b+5)=0
yes so
what do i do next
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if you multiply two terms and you get zero, that means one or the other must be 0
so it is (-5,0)
you know b*(b+5)=0 first case: b is zero. b=0 second case: b+5=0 to find b, add -5 to both sides to get b+5-5= 0-5 or after simplifying b= -5 so b can be 0 or -5
thank you it is correct
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