Jerry has taken a random sample of students and determined the number of electives that each student in his sample took last year. There were 19 students in the sample. Here is the data on the number of electives the 19 students took: 6, 6, 8, 7, 7, 7, 8, 9, 10, 8, 7, 6, 9, 6, 8, 7, 9, 7, 10. The mean of this sample data is 7.63.

What is the sample proportion of students who took fewer than the mean number
of electives?

10/19
6/19
7/19
There is not enough data to answer this question

Question

Jerry has taken a random sample of students and determined the number of electives that each student in his sample took last year. There were 19 students in the sample. Here is the data on the number of electives the 19 students took: 6, 6, 8, 7, 7, 7, 8, 9, 10, 8, 7, 6, 9, 6, 8, 7, 9, 7, 10. The mean of this sample data is 7.63.

What is the sample proportion of students who took fewer than the mean number 
of electives?

10/19
6/19
7/19
There is not enough data to answer this question

gabebae · Answer

The mean is basically adding up all the numbers and dividing them by 19

gabebae · Answer

nevermind I didn't read all of it

swolesammy · Answer

10/19

anonymous · Answer

thank you :)