A golf ball is struck a mighty blow from a driver, lauching it at an angle of θ=10.1o.

The golf ball has been constructed to current professional standards for mass and size:

mB=45.9g and RB=21.5mm.

The impact between the club and the ball may be crudely modelled as a uniform (average) force of F=43kN for a duration Δt=43 μs through a line of action such that b=3.27mm.

Hint: You may assume the impact is sufficiently brief that the ball does not change orientation during the impact.

Question

A golf ball is struck a mighty blow from a driver, lauching it at an angle of θ=10.1o.

The golf ball has been constructed to current professional standards for mass and size:

mB=45.9g and RB=21.5mm.

The impact between the club and the ball may be crudely modelled as a uniform (average) force of F=43kN for a duration Δt=43 μs through a line of action such that b=3.27mm.

Hint: You may assume the impact is sufficiently brief that the ball does not change orientation during the impact.

anonymous · Answer

a)What is the centre of mass speed of the ball ( vG)immediately after impact?
b)What is the magnitude of the angular velocity of the ball ( ω) immediately after impact?
c)What is the magnitude of the velocity of the point A ( vA), on top of the ball, immediately after impact?

anonymous · Answer

This is the diagram:

anonymous · Answer

@IrishBoy123, It would be awesome if you could help me with this question. You've been great at explaining my past questions.

badhi · Answer

from newtons second law,$$F = \frac{mv_1-mv_2}{\delta t}$$
From this I think you can find the speed which the ball is traveling

anonymous · Answer

I still don' understand, I substituted the values of F,m,v and change in t and still got the wrong answer for a. I assumed that initial velocity was 0, and F, m and t was given.

anonymous · Answer

Sorry, was mistaken. Simply entered a wrong value.