Question

At noon, ship A is 170 km west of ship B. Ship A is sailing east at 40 km/h and ship B is sailing north at 20 km/h. How fast is the distance between the ships changing at 4:00 PM?

Answer 1

This is a calculus problem

Answer 2

What we are given:
dx/dt = 40km/j
dy/dt = 20km/h
distance between the ships is d^2=ax^2+by^2

Answer 3

d^2=(40t-170)^2+(20t)^2

Answer 4

@M0j0jojo #PowerPuffGirls

Answer 5

yup the diagram makes sense

Answer 6

yup

Answer 7

wait should the x-component be negative?

Answer 8

-10km?