cosθ tanθ can someone walk me through this will give medal
Can u write tanθ in terms of sinθ and cosθ?? :)
kind of
For example- if you have cotθ and you are asked to write it in terms of sinθ and cosθ then u just have this- Cotθ =cosθ/sinθ Like this can u write tanθ in terms of sinθ and cos??
tanθ=tanθ/cosθ
No this is not correct. The correct value of tanθ - Tanθ =sinθ/cosθ So now u have a new form of tanθ Try to put it in ur expression and try to solve it
Do cosθ(sinθ/cosθ).
im really lost
Then you really need to study this: http://www.sosmath.com/trig/Trig5/trig5/trig5.html
ok
can you please show me how to answer this
you really need to familiar with trig identities look at the link and write these down n your notebook :-]
as mentioned by imqwerty reciprocal identities: \[\large\rm \tan \theta = \frac{\sin \theta}{\cos \theta}\] so you can replace tan with sin/cos in the original question
make sense ?
yes
alright then \[\large\rm cos \theta * \tan \theta \] this is the question rewrite tan theta in terms of sin /cos
tanθ=sin/cos
right if tan theta = sin/cos then you substitute tan for sin/cos in this expression \[\large\rm cos \theta * \tan \theta \]
sp it would be just sine/cosine
just tan theat = sin/cos
\[\large\rm cos \theta * \color{Red}{\tan \theta} \] replace tan tehta with sin/cos
and then simplify:=))
sinθ
\[\large\rm cos \theta * \color{Red}{\frac{ sin \theta}{ cos \theta}} \] in order to simplify this we need to rewrite tan in terms of sin cos tan =sin/cos so we replaced tan with sin/cos then simplify
that's correct.
that's same as \[\large\rm \cancel{ x}*\frac{y}{\cancel{x}}\]
so my answer would be sinetheta
right.
thank you for your help
np and please write these identities n ur notebook it would make ur life easier :=))
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