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Mathematics 16 Online
OpenStudy (anonymous):

PLEASE HELP ME! i have done this problem multiply times and i don't get it right. At the beginning of a week, a stock’s price is $9.40 per share. For that entire week, the stock’s price decreased at a steady rate of $0.20/day. Christine graphs the price of the stock versus time. She plots the price of the stock along the vertical axis, and she plots time in days along the horizontal axis. What is the y-intercept of the line?

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

Lets try and make an equation out of it, Y=9.40-.20x where Y is the price of the stock, 9.40 is the original price of the stock, and -.20x is the change in price and x is the amount of days(time).

OpenStudy (anonymous):

To find the Y intercept, you want to find where the graph crosses the Y-Axis, for a graph to cross the Y-Axis, what does X have to be equal to (what is the value of X)

OpenStudy (anonymous):

|dw:1446253307215:dw| That visual might be able to help. The open Circle could be interpreted as a Y-intercept

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