Question

http://prntscr.com/8xcptk

Answer 1

@Directrix

Answer 2

For the first problem, you can use x = -b/2a to crank out the x coordinate of the vertex.

To help you get started, we can do the first problem = -8x^2 + 4x - 2.

a = -8, b = 4 and c = -2.

x ver = -4/2(-8) = -4/(-16) = + 14. Option A does not have a negative x coordinate of its vertex.

Use the same process to check out the others.

Answer 3

@kittymeow101 Do you have an answer yet? No rush.

Answer 4

the two options with a negative x coordinate are options b and c

Answer 5

Yes, that is what I got.

Answer 6

On #2, the vertex of the parabola is a point on the parabola.

So, it has to satisfy the equation for the parabola.

x-coordinate of vertex (1/2) and looking for corresponding y value

y = - 2 * (1/2) ^2 + 2* (1/2) - 3

You begin by replacing the x value of the vertex in for x in the equation of the parabola.

Answer 7

Look in the options and see if any of them look like that.

Answer 8

option D

Answer 9

I agree.

Answer 10

ty

Answer 11

You are welcome.