Question

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Answer 1

On the table problem, the first two tables do not show points that could be points of a function. In a function, a given x value is paired to one y for that x.

On the first table, x is sent to 5 different y values for the x value of 2.

Answer 2

The same thing happens on the second table. The relationship is not a function so the table cannot be that of a quadratic function or any other function.

Answer 3

so its between the last two tables

Answer 4

On the third table, would you look at the last value of x in that table and post what you see as the value of x. It's fuzzy on my side of the computer.

Answer 5

the last value on the x side is 5

Answer 6

Okay. Of the 5 points, four have the same y value and flatline below the x axis. I have not seen a quadratic function behave that way.