Question

A sparrow flies to see a friend at a speed of 4 km/h. His friend is out, so the sparrow immediately returns home at a speed of 5km/h. The complete journey took 54 minutes. How far away does his friend live?

Answer 1

D = Rate * Time -- Every Time Go!

Answer 2

let distance be x km
while going to meet 4km/h
time taken = x/4

return speed = 5km/h
time = x/5

x/5 +x/4 = 54/60
(4x+5x)/20=54/60
9x=54*20/60
9x=18
/9
x= 2km
Answer is 2km

Answer 3

I know the answer but I need explanation...

Answer 4

I just gave you it?

Answer 5

And thus we see that simply dumping your answer is an insufficient response. It's also contrary to the Code of Conduct.

Answer 6

x/5 +x/4 = 54/60 how from this became (4x+5x)/20=54/60 this

Answer 7

I explained it though

Answer 8

GabeBae by the way your answer is copied from another site so i did not see smth new from you

Answer 9

Distance = Rate * Time -- This is what you need.

Let's use Gabe's definition: x is the Distance <== Very important to WRITE THIS DOWN.

Trip Out: x = Rate * Time = (4 km/h)*(Time Out)
Notice the very clear and direct usage of the basic formula, Distance = Rate * Time

Trip Back: x = Rate * Time = (5 km/h)*(Time Back)
Notice the very clear and direct usage of the basic formula, Distance = Rate * Time

We also know that (Time Out) + (Time Back) = 54 min = (54/60) hr

All that remains is for you to demonstrate your best algebra skills.

Answer 10

Thank you so much Mr. Tkhunny! That is the best professional explanation.

Answer 11

Was this a test of explanations? We like Gabe, too. People who are willing to help are very valuable. A little practice might improve the presentation, but we do NOT want to discourage the effort.

Answer 12

Google is a very close friend of mine :)

Answer 13

@GabeBae That's good. It is a valuable resource. You should use it to develop your own style. :-)

Answer 14

Style? I'm more of a science person but i'm not taking science for this semester