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Use the Limit comparison test to find......
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Hey!
Take a look at limit comparison test https://s3.amazonaws.com/upload.screenshot.co/de1e24aa53
I did, but i don't understand how they multiplied the an and the bn
\(a_n = \dfrac{1}{\sqrt{n^2+1}}\) \(b_n = \dfrac{1}{n}\) \(\lim\limits_{n\to\infty} \dfrac{a_n}{b_n}=?\)
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