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Find the product. (y 2)5 · y 8
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Is that \[(y ^{2})^{5}.y ^{8}\]
yes
You use the power rule which says: \[\large (x^a)^b = x^{a \times b} \] And then use the multiplication power rule with the same exponents: \[\large a^b \times a^c = a^{b+c} \]
Sorry i meant the same bases.
So you have: \[\large (y^2)^5 = y^{2 \times 5} = y^{10}\] And then: \[\large y^{10}\times y^8 = y^{10 + 8} = y^{18} \]
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