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OpenStudy (odesseymoore):
Ok
pooja195 (pooja195):
Ok post your problem :)
OpenStudy (odesseymoore):
It's 1/2 n =3/4
pooja195 (pooja195):
You had the answer of 3/2 which was initially correct.
OpenStudy (odesseymoore):
I never gave a answer
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pooja195 (pooja195):
It was on your previous post.
OpenStudy (odesseymoore):
I need help solving the problem so I can write a justification
pooja195 (pooja195):
Ah ok you wrote
"If It's 1/2 n =3/4 then n=3/2"
OpenStudy (odesseymoore):
I could stay focused on my previous post
OpenStudy (odesseymoore):
Couldn't
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pooja195 (pooja195):
lol its alright ok im going to explain it :)
OpenStudy (odesseymoore):
Ok
pooja195 (pooja195):
\[\huge~\rm~ \frac{ 1 }{ 2 }n=\frac{ 3 }{ 4 }\]
pooja195 (pooja195):
Any ideas on what the first step is?
OpenStudy (odesseymoore):
To find n
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pooja195 (pooja195):
\[\huge~\rm~ \frac{ 1 }{ 2 }n(2)=\frac{ 3 }{ 4 }(2)\]
We multiply by the reciprocal
pooja195 (pooja195):
N cancels out
\[n=? \]
do the solving... 3/4 x 2=?
OpenStudy (odesseymoore):
3/6
OpenStudy (anonymous):
no
pooja195 (pooja195):
You did something wrong.
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OpenStudy (odesseymoore):
1/3
pooja195 (pooja195):
Hold on
You should have gotten 6/4
2 x 3 /4
6/4
pooja195 (pooja195):
Now you can simplify that to get the correct answer :)
pooja195 (pooja195):
Need help?
pooja195 (pooja195):
@OdesseyMoore are you there?
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pooja195 (pooja195):
Divide the numerator and denominator by 2
\[\huge~\rm~\frac{ 6/2=? }{ 4/2=? }\]
imqwerty (imqwerty):
u put 2 '=' signs
imqwerty (imqwerty):
clearly wrong
pooja195 (pooja195):
That is a way of getting the fraction.
imqwerty (imqwerty):
ok
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OpenStudy (anonymous):
What's next?
OpenStudy (odesseymoore):
3/2
OpenStudy (anonymous):
x = ?
pooja195 (pooja195):
Good :)
pooja195 (pooja195):
@OdesseyMoore That is the justification for the problem
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imqwerty (imqwerty):
n=9/6
is also correct
OpenStudy (odesseymoore):
Thank you now there one more mind helping
pooja195 (pooja195):
It's correct but it would be wrong because fractions can be simplified.
imqwerty (imqwerty):
yea sure np B)
pooja195 (pooja195):
@OdesseyMoore yes :)
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OpenStudy (anonymous):
You're welcome @OdesseyMoore
OpenStudy (odesseymoore):
0=2(r-3)+4
pooja195 (pooja195):
0=2(r−3)+4
0=(2)(r)+(2)(−3)+4(Distribute)
OpenStudy (anonymous):
im starting to suspect cheating here. Why so many questions? You should of been able to understand it now after 3+ problems.
imqwerty (imqwerty):
i agree with @V_for_Vengeance
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OpenStudy (anonymous):
I sense someone is helping someone cheat. Which is against CoC.
Law 3, chapter 4 line 8
imqwerty (imqwerty):
maybe this is his/her test
pooja195 (pooja195):
Seriously? If you guys have nothing nice to say don't say it quit spamming ever single post this user asks a question on.
pooja195 (pooja195):
If you want to continue spamming then leave
pooja195 (pooja195):
@OdesseyMoore Can you distribute?
0=2(r−3)+4
\[\huge~\rm~0=(2)(r)+(2)(−3)+4(Distribute)\]
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OpenStudy (zale101):
Are you familiar with distributing @odesseymoore ? We can go over that for you.
OpenStudy (odesseymoore):
A little bit
imqwerty (imqwerty):
@OdesseyMoore please tell ur approach to the prblm
and the point where ur stuck
this will help us explain u better
OpenStudy (odesseymoore):
This Is also justification
OpenStudy (zale101):
I agree with @imqwerty . If you try the problem and work it out here, we can see the mistake your making and we can pint it out for you.
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OpenStudy (zale101):
point*
imqwerty (imqwerty):
:)
OpenStudy (zale101):
It would be better to show your attempts. For ex. Post a problem after you work it out. And post your work here.
imqwerty (imqwerty):
it will also save time
OpenStudy (zale101):
Yep^
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OpenStudy (odesseymoore):
Never mind my mom is home she'll help me finish thank you guys for helping me
OpenStudy (zale101):
This is your question:
0=2(r−3)+4
Try to solve it, then post your work here.
imqwerty (imqwerty):
try the prblm as much as u can
if ur not getting it then also u keep doin it ..try diff ways...don't think that ur wasting ur time in doin it cuz the time is not wasted its utilized
after trying out the prblm so many times when u get a single hint u get the answer at once
OpenStudy (zale101):
Always try solving your questions before asking them. It helps and saves time! :)
OpenStudy (zale101):
Anytime
All thanks to everyone who've helped you!
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