If the sin 60° = square root of three over two, then which statement is true?
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OpenStudy (anonymous):
cos 30° = square root of three over two, because the cosine and sine are complements
cos 120° = square root of three over two, because the cosine and sine are supplements
cos 30° = 0, because the cosine and sine are complements
cos 120° = 0, because the cosine and sine are supplements
OpenStudy (baru):
sin and cos are complemntary
which means
\(cos(\theta) = sin(90-\theta) \)
OpenStudy (baru):
so which do u think the answer is?
OpenStudy (anonymous):
don't quite understand
OpenStudy (baru):
just substitute \( \theta=60^0 \) and see what u get
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OpenStudy (baru):
* substitute in the formula i gave
OpenStudy (anonymous):
so cos 30=0
OpenStudy (anonymous):
is that right or is it cos 30= sr3/2
OpenStudy (baru):
did u try substituting in the formula like i said?
OpenStudy (anonymous):
yes i did i think the answer is a, cos 30= sr3/2 i that right?
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