Question

What is the simplified form of 3 over 2x minus 5 + 21 over 8 x squared minus 14x minus 15 ?

6 times the quantity 2 x plus 5 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
6 times the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
6 time the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
6 times the quantity x plus 1 end quantity over the quantity 2x plus 5 end quantity times 4 x plus 3

Answer 1

@Baby_Bear69

Answer 2

@welshfella

Answer 3

@KendrickLamar2014

Answer 4

@♪Chibiterasu

Answer 5

@Nnesha

Answer 6

ello love :D need some help? @Motown117

Answer 7

yes i need help

Answer 8

\[\huge\rm \frac{ 3 }{ 2x-5 } +\frac{21}{8x^2-14x-15}\] like this ?

Answer 9

yes

Answer 10

first factor the quadratic equation

Answer 11

can you walk me through how to do this?

Answer 12

you got this! :D @nnesha

Answer 13

alright \[\huge\rm 8x^2-14x-15\]
multiply AC (a =leading coefficient, c=constant term) ,

Answer 14

8 times -15 = -120
now find two number when we multiply them we should get product of AC and when we add or subtract them we should get middle term which is -14 in this equation

Answer 15

7times -7

Answer 16

thats wrong isent it?

Answer 17

hmm this is AC method to factor
the product of 2 number should be equal to AC
and sum = -14
so find two number if you multiply them you should get -120( product of a and c =8 times -15)

Answer 18

and when you add/subtract them you should get -14

Answer 19

6 times -20

Answer 20

right and since the leading coefficient isn't one we need to factor by grouping
carry down the first and last term and write both numbers in middle