Question

A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey results for the first-, second-, and third-period classes are as follows:

First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0

Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3

Which is the best measure of center for first period and why?

Mean, because there are no outliers that affect the center
Median, because there is 1 outlier that affects the center
Interquartile range, be

Answer 1

could someone help i am confused on this ?

Answer 2

answer choices

Mean, because there are no outliers that affect the center
Median, because there is 1 outlier that affects the center
Interquartile range, because there is 1 outlier that affects the center
Standard deviation, because there are no outliers that affect the center

Answer 3

Measures of central tendency are methods to which an investigator can locate the most central value, or the reoccurring or frequent most value in the set of parameter or statistic. There are three:
Mean. Is the average of the data values
Median. The middlemost value or digit in the data set
Mode. The determining the most frequent parameter To identify which of these three suits the given, arranging them first is a must. Ascending to descending.
Third Period: 0,1,1,1,2,2,2,3,3,3,3 4,4,4,5,8,

The best is mode, why? Because if you observe there is a number most frequent in the data value and it is the fastest way.

Mode = 3

Answer 4

none of the answer choices say mode ? @Killer_Shadow

Answer 5

oh s h i t my bad hang on

Answer 6

I would say the second one

Answer 7

cause there is an outlier

Answer 8

then i guess it would b the third

Answer 9

but the third one has an outlier of 8 ? @hihi67

Answer 10

i guess so thanks @Killer_Shadow

Answer 11

no problem