Question

Determine f(-2), f(-1), f(0) and f(1). If any of these are undefined enter "undefined" as the answer.

Answer 1

You have to plug each one into the appropriate equation for the function. The function you have in your attached file tells you where it is defined.

Answer 2

Now if you plug each one into its appropriate equation you will get the answers.

Answer 3

How do I know which is the appropriate one?

Answer 4

Lets look at it this way. The first line reads

2x+1 if -2<x<=0

The way you would read the second part of this is: if negative two is less than x which is less than or equal to zero. A simpler way of putting this might be in interval notation where it would read something more like (2,0]. To say it outright for the values in the range of -2 to 0 the equation for this piecewise function is 2x+1, however the number -2 itself is not included in this because it only says < instead of <=.

Answer 5

@JosephTheAusom so -1 would work for that one

Answer 6

yes negative one would work for that part. You just plug it in and solve

Answer 7

I got -1 for f(-1) it looks like f(-2) would be undefined then?

Answer 8

Yes exactly.

Answer 9

would f(1) work in 3x-2?

Answer 10

since its 1 <= x <2

Answer 11

yes because it use <= which means it includes the value. I think you are catching on.

Answer 12

For f(1) I got 1 for f(0) im a little confused where that one goes would it be the 3x^2+2 the reason I ask is because 0<x<1 and it doesent say 0<=

Answer 13

@JosephTheAusom Does this look right?

f(-2) = undefined
f(-1) = -1
f(0) = 2
f(1) = 1

Answer 14

ok all of those are right except f(0). You had that one correct in the previous post. And reasoning for it was spot on in that post too. It should be f(0)=1

Answer 15

so f(0) =1 and f(1)= 1 too?

Answer 16

so in this problem we don't use 3x^2+2

Answer 17

Oh ok I see it now I use the first formula thanks for you help :)

Answer 18

Yes absolutely, sorry for the late reply!