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OpenStudy (anonymous):

Quick Question! If a rock falls for 1 second, what is its average speed during that second ? The answer is 16 ft/s, but I don't understand why. Thanks for the help!

OpenStudy (anonymous):

@amistre64 @ganeshie8 @Nnesha @AlexandervonHumboldt2 @Whitemonsterbunny17 @Ashleyisakitty @Jaynator495 @Squirrels @TheAsker2002 @Teddyiswatshecallsme

OpenStudy (anonymous):

The initial velocity is zero. After falling for 1 second, its velocity is 32 ft/s. The average of the two velocities is 16 ft/s.

OpenStudy (anonymous):

where'd you get 32 ft/s from?

OpenStudy (anonymous):

@ospreytriple

OpenStudy (anonymous):

\[v=a \Delta t\]with acceleration of gravity = 32 ft/s^2 and the time interval = 1 s.\[v=\left( 32 \frac{ft}{s^2} \right)\left( 1 s \right) = 32 \frac{ft}{s}\]

OpenStudy (anonymous):

ohh, I get it. Thanks for the help, I really appreciate it! :)

OpenStudy (anonymous):

You're welcome

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