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Quick Question! If a rock falls for 1 second, what is its average speed during that second ? The answer is 16 ft/s, but I don't understand why. Thanks for the help!
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The initial velocity is zero. After falling for 1 second, its velocity is 32 ft/s. The average of the two velocities is 16 ft/s.
where'd you get 32 ft/s from?
@ospreytriple
\[v=a \Delta t\]with acceleration of gravity = 32 ft/s^2 and the time interval = 1 s.\[v=\left( 32 \frac{ft}{s^2} \right)\left( 1 s \right) = 32 \frac{ft}{s}\]
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ohh, I get it. Thanks for the help, I really appreciate it! :)
You're welcome
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