Question

y=x^3-5x^2+9x-45
you have to find all the zero's.

Answer 1

Try dividing x^3-5x^2+9x-45 by x-5

Answer 2

ok i will try that :)

Answer 3

it didnt work :(

Answer 4

@ missiey, @graveboat789, @Spring98

Answer 5

@gravyboat789

Answer 6

I'm sorry but I don't know this..

Answer 7

ok thanks :)

Answer 8

\[\frac{x^3-5 x^2+9 x-45}{x-5}=x^2+9 \]

Answer 9

hey i foud the other zero; they are 5,-3i,3i....(:

Answer 10

*found