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Mathematics 15 Online
OpenStudy (chris215):

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OpenStudy (anonymous):

ok so do you under stand any of the qustion i do thats why i am asking please for give my spelling ok

OpenStudy (chris215):

my first thought was that i plug in and solve for x = 100 to x = 102 but im not sure if you could explain this to me that would be great

OpenStudy (anonymous):

ok so its just tring to make it confusing but i can help all it wants is what is x = dose that mak senes tell me what you think the answer is and i will tell you if your wit ok

OpenStudy (anonymous):

do you understand

OpenStudy (chris215):

i plugged in 100 for x and got 9600

OpenStudy (chris215):

then i pluged in 102 and git 10004 idk i feel like thats wrong

OpenStudy (anonymous):

yes it is it soo funy i looked at it and was like thats wrong i go whith 9600

OpenStudy (chris215):

so what i did was right for part a ? now do i subtract 10404-9600 to get the rate of change

OpenStudy (anonymous):

its nice to meet you btw are you new i am and yes that exacly what you do

OpenStudy (chris215):

ok thanks and u too im not new though

OpenStudy (superdavesuper):

hint: average rate of change of C with respect to x = [C(x1)-C(x2)] / (x1 - x2)

OpenStudy (anonymous):

oh iam just getting used to open study i thout you press enter to post but no it hast to be diffent lol

OpenStudy (anonymous):

if you no the answer superdavver just give it to here no need to be rude

OpenStudy (superdavesuper):

@chris215 so u are missing one step in ur calculation of the average rate of change after the subtraction...

OpenStudy (chris215):

thanks @superdavesuper i got 202

OpenStudy (anonymous):

did you band my brother login

OpenStudy (anonymous):

and your whit you when the laterey

OpenStudy (superdavesuper):

@chris215 oh wait - plz redo ur C(102) calculation...

OpenStudy (superdavesuper):

nvd 202 IS the right ans thou @chris215 :)

OpenStudy (chris215):

oh ok thanks :) i dont really understand part b though

OpenStudy (superdavesuper):

btw part a ans should be 202 dollars per unit. Part b is asking for instantaneous rate of change. So u will need to differenitate C(x) by x. U know how to do that?

OpenStudy (chris215):

I dont @superdavesuper

OpenStudy (anonymous):

do you steel need help

OpenStudy (chris215):

yes lolll

OpenStudy (anonymous):

OK what is your quotation i would of answered the anther one but my concretion Brok down

OpenStudy (chris215):

is the derivative 2x then i do 2(100) = 200?

OpenStudy (anonymous):

your whit so whats the problem did somone tell you your wrong or is that not the anser and thank you for being nice to me

OpenStudy (anonymous):

are you stell there

OpenStudy (chris215):

yeah no i just wanted to make sure i got it right thanks so much for your help!

OpenStudy (anonymous):

yep np can you give me a faver

OpenStudy (chris215):

yeah?

OpenStudy (anonymous):

when you hit 10 medals can you give me one please alot of peple tell me that they will but they dont and can you help me tomwoo on my math test please

OpenStudy (anonymous):

and what grade or you in

OpenStudy (anonymous):

are you there

OpenStudy (anonymous):

did you leave

OpenStudy (superdavesuper):

@chris215 dC/dx = 2x so u got it :) dont forget to add units to ur ans thou!

OpenStudy (anonymous):

ya what do you think it is

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