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Find the limit as x approaches 3?
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\[\lim_{x \rightarrow 3} = (\sqrt{2x+3}-\sqrt{3x})/(x^2-3x)\]
I know the limit is -0.0555 or -1/18 from graphing it but I can't figure out how to find the limit algebraically
Try multiplying top and bottom by \(\Large \sqrt{2x+3}+\sqrt{3x}\) to rationalize the numerator.
okay thank you! @jim_thompson5910
let me know if you're able to finish up or not
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i was able to finish it up, thanks again!
you're welcome
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