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Mathematics 16 Online
OpenStudy (anonymous):

Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV. What will be the location of T' in the image trapezoid S'T'U'V'? A. (18, -2) B. (18, 2) C. (15, -2) D. (15, 2)

OpenStudy (anonymous):

@Rubyjadeluv

OpenStudy (anonymous):

@rhettwalker14

OpenStudy (anonymous):

@pooja195

OpenStudy (anonymous):

sorry but i suck at math

OpenStudy (anonymous):

@wes_is_here

OpenStudy (anonymous):

its ok do you know who does not?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@SamsungFanBoy

OpenStudy (anonymous):

@dusdog

OpenStudy (anonymous):

@Needhelpp101

OpenStudy (anonymous):

ello love :D

OpenStudy (anonymous):

hi :) can you help?

OpenStudy (anonymous):

yes love, do you have a picture of the graph? :)

OpenStudy (anonymous):

oh yea lol hang on :) thnx

OpenStudy (anonymous):

alright haha

OpenStudy (anonymous):

OMG SORRY IM TAKING LONG HANG ON

OpenStudy (anonymous):

oops sorry had the caps on

OpenStudy (anonymous):

LOL ITS FINE IM DOING WORK ALSO.... TAKE YOUR TIME haha

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

try that if you cant see it hang on a lil more pls lol

OpenStudy (anonymous):

i cant open it haha xD alright

OpenStudy (anonymous):

PPPPTT!!!!!!!!!! xP

OpenStudy (anonymous):

ugh sorry lol the screen shot is seriously not saving :/

OpenStudy (anonymous):

haha its fine no rush... :D

OpenStudy (anonymous):

hurry up! haha jus kidding

OpenStudy (anonymous):

OpenStudy (anonymous):

FINALLY!!! lol

OpenStudy (anonymous):

sorry for the wait lol

OpenStudy (anonymous):

there you go darlin' haha FIVE HOURS LATER xP haha its fine... lets get to work :)

OpenStudy (anonymous):

lol it was at least like 10 min hahahha

OpenStudy (anonymous):

okay fine 10 years xD haha but what do you know about transformations?

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

and ik nothing :/

OpenStudy (anonymous):

if i were to tell you the transformation were to be: x,y --> x-10, y+3 would you be able to apply that to the trapezoid?

OpenStudy (anonymous):

im confused sorry i have no clue about this lol

OpenStudy (anonymous):

haha thats fine, ill draw it out hold on :)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

sorry i hed it wrong x,y --> x+13, y-3 lol

OpenStudy (anonymous):

lol its ok

OpenStudy (anonymous):

ok after that whats next?

OpenStudy (anonymous):

OpenStudy (anonymous):

so for this transformation we add 13 to the original x coordinate and subtract 3 from the original y coordinate as i did in the picture

OpenStudy (anonymous):

ok i sorta get it but how can i do that for the top shape?

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

two ways: we simply can start at each point and count over to its new point, or we can take our original points and add and subtract the transformation fro m the originals :) chose what you would like to do..

OpenStudy (anonymous):

second choice sounds easier lol

OpenStudy (anonymous):

haha theyre both easy lol, so lets pull out the original points from the graph, what are the points for the trapezoid??

OpenStudy (anonymous):

umm TUVS?

OpenStudy (anonymous):

yes, pull the (x,y) coordinates, do you know how to do that?

OpenStudy (anonymous):

no i dont

OpenStudy (anonymous):

can you show me?

OpenStudy (anonymous):

sure :) so for point U we have (2,6), so that is point U.... do you understand?

OpenStudy (anonymous):

ok let me see hang on

OpenStudy (anonymous):

alright ...

OpenStudy (anonymous):

ok how did you get that?

OpenStudy (anonymous):

the point goes over 2 on the x axis and up 6 on the y axis

OpenStudy (anonymous):

sorry math just doesnt process through my brain lol

OpenStudy (anonymous):

its fine :)

OpenStudy (anonymous):

oooohhhh ok i get it now lol

OpenStudy (anonymous):

i have to leave in a few so yea, no rush but just letting you know :) but yes that is how you find the points (ordered pairs)

OpenStudy (anonymous):

so now find the other points

OpenStudy (anonymous):

noooo lol ok can you help me real quick to find them? like see if im doing it right?

OpenStudy (anonymous):

yes! lol yes i will help as long as i can haha

OpenStudy (anonymous):

so find the points and post them

OpenStudy (anonymous):

haha ok so um 15,-2?

OpenStudy (anonymous):

what point is that?

OpenStudy (anonymous):

i tried to get to point T? lol omg i cant believe i cant get this hahaha

OpenStudy (anonymous):

haha its quite alright but no point T (5,5)

OpenStudy (anonymous):

ugh ok see idk how you got 5,5 lol

OpenStudy (anonymous):

OH NO WAIT!!!

OpenStudy (anonymous):

i was doing it on the negative side lol

OpenStudy (anonymous):

ok this is very confusing

OpenStudy (anonymous):

OpenStudy (anonymous):

lol i got that hahaah

OpenStudy (anonymous):

i want to know how to get my answer lol

OpenStudy (anonymous):

want me to give you the points?

OpenStudy (anonymous):

um pls lol and explain how you got the answer lol pls :)

OpenStudy (anonymous):

so i can know how to do it lol

OpenStudy (anonymous):

like explain the steps pls :)

OpenStudy (anonymous):

ordered pairs are always (x,y): U(2,6) T(5,5) S(3,2) V(1,4) so for U, 2 is our x and 6 is our y so to get the prime (the new points) for this transformation, we add 13 to the x-intercept, and subtract 3 from the y-intercept

OpenStudy (anonymous):

understand?

OpenStudy (anonymous):

why 13 and why 3?

OpenStudy (anonymous):

because that is our transformation

OpenStudy (anonymous):

is that for every problem?

OpenStudy (anonymous):

transformation: x,y --> x+13, y-3 and yes you apply for every point

OpenStudy (anonymous):

ill do the first one :) so: U (2,6) --> (2+13, 6-3) U (2,6) --> (15,3) so our new point (U') is 15,3

OpenStudy (anonymous):

@MariahDimond think you sould help her? its transformations

OpenStudy (anonymous):

im sorry to leave you but i must go now :( @iloveyou;*

OpenStudy (anonymous):

oh ok lol

OpenStudy (anonymous):

thnx for all your help :D

OpenStudy (anonymous):

and for being patient with me too lol

OpenStudy (anonymous):

yea so good luck :) and no problem :D fan me...

OpenStudy (anonymous):

lol love you XD

OpenStudy (anonymous):

@pooja195 could you please help here finish the problem?

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