Question

Please help??? Identify the vertex and the axis of the symmetry of the graph of the function y=3(x+2)^2-3.
a. vertex: (2,-3); axis: x=2
b. vertex: (-2,-3); axis: x=-2
c. vertex: (2,3); axis: x=2
d. vertex: (-2,3); axis: x=-2
I sort of thinking that it is C but I need someone to check and explain. Please :D

Answer 1

C is actually incorrect the correct answer would be B because if we look at the graph we can clearly see that the vertex coordinates are both Negetive.

Answer 2

Do you have to create a function table in order to find the points to graph?

Answer 3

the vertex form is
y = a(x - b) + c

where the vertex is at (a,b)

Answer 4

- and the axis of symmetry is x = b

Answer 5

compare your equation with the above general form and you'll see the answer

Answer 6

So it would be (-2,-3) but where does the -2 come from for the axis

Answer 7

x = b and b = -2