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Mathematics 10 Online
OpenStudy (anonymous):

Im a bit confused can anyone help?

OpenStudy (anonymous):

For the 1st i got 90 which isnt a an answer then for the 2nd one i got 34.63 which isnt a answer

OpenStudy (anonymous):

@yaya090600

OpenStudy (johnweldon1993):

So the pyramid we have \[\large SA = \frac{1}{2} \times \text{Perimeter of the base} \times \text{Slant Height}\] Since we know sides of the base are all 5 we have 20 for the perimeter...and we know the slant height is 6 sooo \[\large SA = \frac{1}{2} \times 20 \times 6 = 60\]

OpenStudy (anonymous):

ooohh okay

OpenStudy (anonymous):

do you do the same for the 2nd one or?

OpenStudy (johnweldon1993):

Not really...first realize that a pyramid is basically 4 triangles leaning against each other right?|dw:1446665400894:dw| my terrible drawing there XD

OpenStudy (anonymous):

right

OpenStudy (johnweldon1993):

Now if we want the slant height *have to draw this a little slanted because I started slanted |dw:1446665488431:dw| It looks like we just have a right triangle with height 4 and base 1.5 right? We just need to find the hypotenuse

OpenStudy (anonymous):

ok

OpenStudy (johnweldon1993):

And I'm sure you know how to do that :)

OpenStudy (anonymous):

yeah

OpenStudy (yaya090600):

sorry i just saw this lol

OpenStudy (anonymous):

no your fine lol

OpenStudy (yaya090600):

do you still need help?

OpenStudy (anonymous):

yeah on the 2nd one i got 34.63

OpenStudy (yaya090600):

do you know how to do the Pythagorean theorem?

OpenStudy (anonymous):

yeah i do

OpenStudy (yaya090600):

ok since the line is in the middle of the pyramid you wont square the 3

OpenStudy (yaya090600):

so 4^2 + 3 = x^2

OpenStudy (anonymous):

so 19?

OpenStudy (yaya090600):

19=x^2

OpenStudy (yaya090600):

so you square root each side

OpenStudy (anonymous):

ok

OpenStudy (yaya090600):

\[\sqrt{19} = 4.359\]

OpenStudy (anonymous):

so do we leave it at 5 since it wants us to round?

OpenStudy (yaya090600):

it rounds to 4.4 which is not one of your options

OpenStudy (anonymous):

so just 4.3

OpenStudy (yaya090600):

thats what i would put lol

OpenStudy (anonymous):

Thanks again!

OpenStudy (yaya090600):

my pleasure

OpenStudy (anonymous):

Im sorry @yaya090600 can you help me with thie fist one I got 60 but its wrong

OpenStudy (anonymous):

im just confused what went wrong

OpenStudy (anonymous):

SA = 1/2*20*6=60 was wrong

OpenStudy (yaya090600):

you can google surface area of a pyramid calculator and put in the length width and height

OpenStudy (anonymous):

i got 90

OpenStudy (anonymous):

its not an answer

OpenStudy (yaya090600):

but you need to find the height first, and you can use the Pythagorean theorem for that

OpenStudy (anonymous):

7.81

OpenStudy (yaya090600):

\[x ^{2} + 5 = 6^{2}\]

OpenStudy (yaya090600):

so the height would be \[\sqrt{31}\]

OpenStudy (anonymous):

so would it be B

OpenStudy (yaya090600):

no

OpenStudy (yaya090600):

your length and width are both 5

OpenStudy (yaya090600):

i got 86

OpenStudy (anonymous):

oh its 85

OpenStudy (yaya090600):

oh i didnt round, its 85

OpenStudy (anonymous):

thank you

OpenStudy (yaya090600):

no prob

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