I'll fan and give medal. The area of a triangle is 25 square iches. Its base (b) is 5 inches. What is its height (a)?
\[Formula: \frac{ 1 }{ 2 }ba\]
be sure plug in your numbers like this
\[25 inches ^{2} = \frac{ 1 }{ 2 }5a\]
then solve for h by dividing both sides by 2.5 \[25inches ^{2} = 2.5h \]
\[\frac{ 25 }{ 2,5 } = 10 inches \]
sorry that should be 2.5, then you would get the height to be 10 inches.
and it says to check it so how do i do i check it
you take your answer and plug it back in
\[a = \frac{ 1 }{ 2}bh \]
plug in all your numbers \[25 = (0.5)(5)(10) \]
so clearly 0.5x5 = 2.5 and 10*2.5 = 25 so on the left side we have the same thing. 25 = 25 that's how we know it's right
@expressing.myself00 want me to give you a problem?
maybe later so I can fully get it before y math test but I'm just trying to get this turned in now so I don't stay behind in my classes
do you get what I wrote?
yeah but Imma study it more after I turn this in
so how would dividing both of the sides look? like what would that step of this problem look like?
Okay let me show you
@expressing.myself00 I want to show you the entire process step by step. look this over |dw:1446694431253:dw| we plug in all the values |dw:1446694473341:dw| now we simplify by multiplying 5 times one half and we get this |dw:1446694536214:dw| You see that we MUST solve for H. we do this by getting H by itself. to do THIS we see 2.5 times H we must divide both sides by 2.5 to get H by itself. |dw:1446694585466:dw| Now we check our work. We check our work by plugging everything in. in an equation what we have on the right side must equal what we have on the left side otherwise it's not right. we plug in h = 10 and b = 5 into the original equation and find that 0.5*5 = 2.5x10 = 25. that's our original area so that's how we know it's correct. |dw:1446694660774:dw|
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