Question

What are the domain and x-intercept of:
g(x)=25√-24x+27
??? WILL MEDAL AND FAN!!!

Answer 1

so is the question

\[g(x) = 25\sqrt{-24x + 27}\]

Answer 2

yeah- what's the domain (in interval notation), and what is the horizontal intercept (as a coordinate pair)?

Answer 3

horizontal intercept?

Answer 4

yeah.

Answer 5

I never heard it call that

Answer 6

or x-intercept?

Answer 7

x-intercept can be found by replacing y with 0 and solving for x

Answer 8

domain just remember numbers under square root thingy must be positive or 0

Answer 9

ok... so the x-intercept will also also be the upper limit on the domain

you need to look at the part inside the square root...

remember, you can't take the square root of a negative so you need to solve

\[-24x + 27 \ge 0\]

to get the domain

the x-intercept, you need to solve

\[-24x + 27 = 0\]

Answer 10

hope it all makes sense

Answer 11

'kay, so

-24x=-27
-27/-24=x
x=1.125

so the x intercept would be (1.125,0) and the domain would be (-oo,1.125)?

the domain one sounds weird- I feel like there's some test or something to know whether it's (-oo,1.125) or (1.125,oo)

*oo is how I was taught to type infinity

Answer 12

well remember, in the domain, you solved

\[-24x + 27 \ge 0\]

to the domain contains 9/8 or 1.1.125

so just change the bracket

and everything else is correct

Answer 13

Thanks!