Generate the first 5 terms of this sequence: (1 point)
f(1) = 1 and f(2) = 2, f(n) = f(n - 1) + f(n - 2), for n > 2.
1, 2, 3, 4, 5
1, 2, 3, 5, 7
1, 2, 3, 5, 8
1, 3, 5, 7, 9
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OpenStudy (misty1212):
HI!!
OpenStudy (anonymous):
Hi, Please help I'm stuck..
OpenStudy (misty1212):
you know \(f(1)\) adn \(f(2)\) right?
OpenStudy (misty1212):
what \(f(n) = f(n - 1) + f(n - 2), \) means is that the next number is what you get when you add up the last two
OpenStudy (misty1212):
so for example \(f(3)=f(2)+f(1)\)
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OpenStudy (misty1212):
you got that?
OpenStudy (misty1212):
starts with \(1,2\) then the next one is \(1+2=3\)
OpenStudy (anonymous):
Wait what??
OpenStudy (anonymous):
@misty1212 I dont understand how to do more?
OpenStudy (misty1212):
add the previous two to get the next one
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OpenStudy (anonymous):
To get any or just the next one?
OpenStudy (misty1212):
\[1,2,\overbrace{3}^{1+2}\]
OpenStudy (anonymous):
so then 2+3 ?
OpenStudy (misty1212):
so we are at \(1,2,3\) next will be yes that
OpenStudy (anonymous):
1,2,3,5,8?
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OpenStudy (anonymous):
@misty1212 right?
OpenStudy (misty1212):
yes
OpenStudy (misty1212):
sure
OpenStudy (anonymous):
For the function f(x) = x + 7, what is the ordered pair for the point on the graph when x = 2b? (1 point)
(2b, 2b + 7)
(2b, x + 7)
(x, x + 7)
(x, 2b + 7)
OpenStudy (misty1212):
if \(x=2b\) then in the first slot for \((x,y)\) you need to see \(2b\)
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OpenStudy (anonymous):
so 2b + 2b?
OpenStudy (misty1212):
?
OpenStudy (anonymous):
2b + y?
OpenStudy (misty1212):
\[f(x)=x+7\\
f(2b)=2b+7\]
OpenStudy (anonymous):
What?..
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OpenStudy (misty1212):
lol i guess you are confused, lets go slow
OpenStudy (misty1212):
you have a function \(f(x)=x+7\) which means, take your number, whatever \(x\) is, and add \(7\) to it
OpenStudy (anonymous):
2b + 7?
OpenStudy (misty1212):
so for example \[f(3)=3+7=10\\
f(0)=0+7=7\\
f(-7)=-7+7=0\\
f(\pi)=\pi+7\\
f(\heartsuit)=\heartsuit+7\] and so on
OpenStudy (misty1212):
yes so \[f(2b)=2b+7\] is the second coordinate
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OpenStudy (anonymous):
what would be the first?
OpenStudy (misty1212):
yes, a very very rare A
OpenStudy (anonymous):
A?
OpenStudy (misty1212):
yup
OpenStudy (anonymous):
OKay, i just have one more can you help me on this last one?
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