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Solve: 2n(2n + 2)=10+2n (squared)
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distribute 2n to (2n+2) first
I did it step by step but I didn't get the right answer surprisingly...
\(2n(2n + 2)=10+2n^2\) ?
Yes
What you have to do first is distribute 2n to everything in the parentheses behind it, so you would get 4n(squared) + 4n = 10 + 2n(squared).
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Next you would subtract 2n2 from both sides so that your value of 10 is by itself.. Now you have 2n^2 + 2n = 10
What answer do you get?
\(2n(2n + 2)=10+2n^2\\4n^2 + 4n=10+2n^2\\2n^2+4n-10=0\\2(n^2+2n-5)=0\\n^2+2n-5=0\\n=-1 \pm \sqrt 6\)
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