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Write a quadratic function in standard form having zeros of -5 and 1.
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Use this f(x)=(x-a)(x-b) where a and b are your zeros.
I don't get what that equation is though.. @math&ing001
Example suppose your zeros are 9 and -7 f(x) = (x-9)(x-(-7)) = (x-9)(x+7) = x^2+7x-9x-63 = x^2 - 2x - 63 so f(x)= x^2 - 2x - 63 is the quadratic function in standard form
oh ok!!
would this one be x^2+4-5?
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@math&ing001
Yep ! Don't forget the x near 4.
oh thank you!!! <3
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