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WILL FAN AND MEDAL FOR ANSWER. 7. If sinθ=4/5, what is the value of cosθ in quadrant 1? A. 9/25 B. 16/25 C. 3/5 D. 5/4
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it is not \[\sin^2(4/5)+\cos^2(x)=1\] it is \[(\frac{4}{5})^2+\cos^2(x)=1\]
easier to draw a right triangle |dw:1446778812861:dw|
there is a picture of an angle whose sine is \(\frac{4}{5}\) find the missing side via pythagoras, or just remember the mother of all right triangles 3 - 4 - 5 then you can take any trig ratio you like
Thank you for pointing out my mistake.
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