Geometry Help!!
|dw:1446883962252:dw|
Finf FH
give me 5 minutes
are we missing some information? like an angle maybe?
no angle is given
except those 90 degrees
very tricky. I'll need more time to think
a clue: BS=EF-DE (there is a theorem like that in isosceles triangles)
where did you get that from?
a rule i don't know how to prove
there doesn't appear to be enough information to solve FH Let me do some research and I'll get back to you
I need to clarify your drawing Does HE = 10, HB = 5 & SB = 12 ?
OK, I've just worked out the base angles of the isosceles triangle so give me another 5 minutes or so and I'll have the answer to FH
I've got arctan2 as the base angles which is 63.4 degrees
I get FH= 7.99 which is close enough to 8
Have they given you an answer?
answer is 8
OK. Thats good, so my method is correct !! I would assume you want to know how I got that?
of course i do
its long and quite complicated so I think its best that I write it out and send it to you as a pdf
@imqerty, what are you up to? if you're going to post the solution then i wont waste my time writing it out
m eating food :) i ws doing it with coordinate geometry :)
have you managed to arrive at the same answer?
no i ws still working on it
OK, I'd be interested to see your approach. I'll go ahead and write out the geometric solution using algebra and post it up then
ok :) i'll post the solution after food B)
please have a look at this question as well
hold your horses. I'm still writing out the solution to the last one
coordinate geometry is getting too complicated i think i shuld try another method :)
ok, stand by. I'm just about to post the solution
This corresponds to the drawing file attachment that you sent for A, B and C
WOW do we know tan2= x degrees in our memory in the exams :D thanks anyway..
haah :D nice solution i ws doin something similar :) wait a sec ima post it
without using a calculator you could probably use sinα = 2/sqrt3 and cosα = 1/sqrt3 to work out FH from there. I reckon it can be done without working out a value for alpha
from eq 1 and eq2 we can get x and trigonometric values frm which we can calculate AF
Yes, I was right it can be done without evaluating α sin(2α -90) = 2sin^2(α) -1 = 5/3
the second eq i got from this- BS=EF-DE
so you don't need a calculator
Join our real-time social learning platform and learn together with your friends!