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Mathematics 20 Online
OpenStudy (anonymous):

Geometry Help!!

OpenStudy (anonymous):

|dw:1446883962252:dw|

OpenStudy (anonymous):

Finf FH

OpenStudy (alekos):

give me 5 minutes

OpenStudy (alekos):

are we missing some information? like an angle maybe?

OpenStudy (anonymous):

no angle is given

OpenStudy (anonymous):

except those 90 degrees

OpenStudy (alekos):

very tricky. I'll need more time to think

OpenStudy (anonymous):

a clue: BS=EF-DE (there is a theorem like that in isosceles triangles)

OpenStudy (alekos):

where did you get that from?

OpenStudy (anonymous):

a rule i don't know how to prove

OpenStudy (alekos):

there doesn't appear to be enough information to solve FH Let me do some research and I'll get back to you

OpenStudy (alekos):

I need to clarify your drawing Does HE = 10, HB = 5 & SB = 12 ?

OpenStudy (anonymous):

OpenStudy (alekos):

OK, I've just worked out the base angles of the isosceles triangle so give me another 5 minutes or so and I'll have the answer to FH

OpenStudy (alekos):

I've got arctan2 as the base angles which is 63.4 degrees

OpenStudy (alekos):

I get FH= 7.99 which is close enough to 8

OpenStudy (alekos):

Have they given you an answer?

OpenStudy (anonymous):

answer is 8

OpenStudy (alekos):

OK. Thats good, so my method is correct !! I would assume you want to know how I got that?

OpenStudy (anonymous):

of course i do

OpenStudy (alekos):

its long and quite complicated so I think its best that I write it out and send it to you as a pdf

OpenStudy (alekos):

@imqerty, what are you up to? if you're going to post the solution then i wont waste my time writing it out

imqwerty (imqwerty):

m eating food :) i ws doing it with coordinate geometry :)

OpenStudy (alekos):

have you managed to arrive at the same answer?

imqwerty (imqwerty):

no i ws still working on it

OpenStudy (alekos):

OK, I'd be interested to see your approach. I'll go ahead and write out the geometric solution using algebra and post it up then

imqwerty (imqwerty):

ok :) i'll post the solution after food B)

OpenStudy (anonymous):

please have a look at this question as well

OpenStudy (alekos):

hold your horses. I'm still writing out the solution to the last one

imqwerty (imqwerty):

coordinate geometry is getting too complicated i think i shuld try another method :)

OpenStudy (alekos):

ok, stand by. I'm just about to post the solution

OpenStudy (alekos):

OpenStudy (alekos):

This corresponds to the drawing file attachment that you sent for A, B and C

OpenStudy (anonymous):

WOW do we know tan2= x degrees in our memory in the exams :D thanks anyway..

imqwerty (imqwerty):

haah :D nice solution i ws doin something similar :) wait a sec ima post it

OpenStudy (alekos):

without using a calculator you could probably use sinα = 2/sqrt3 and cosα = 1/sqrt3 to work out FH from there. I reckon it can be done without working out a value for alpha

imqwerty (imqwerty):

:) here- http://prntscr.com/9002sc

imqwerty (imqwerty):

from eq 1 and eq2 we can get x and trigonometric values frm which we can calculate AF

OpenStudy (alekos):

Yes, I was right it can be done without evaluating α sin(2α -90) = 2sin^2(α) -1 = 5/3

imqwerty (imqwerty):

the second eq i got from this- BS=EF-DE

OpenStudy (alekos):

so you don't need a calculator

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